Armstrong number
An Armstrong number of three digits is an integer such that the sum of the cubes of its digits is equal to the number itself. For example, 371 is an Armstrong number since 3**3 + 7**3 + 1**3 = 371.
Program for to check Armstrong number or not.
int main()
{
int number, originalNumber, remainder, result = 0;
printf("Enter a three digit integer: ");
scanf("%d", &number);
originalNumber = number;
while (originalNumber != 0)
{
remainder = originalNumber%10;
result += remainder*remainder*remainder;
originalNumber /= 10;
}
if(result == number)
printf("%d is an Armstrong number.",number);
else
printf("%d is not an Armstrong number.",number);
return 0;
}
{
int number, originalNumber, remainder, result = 0;
printf("Enter a three digit integer: ");
scanf("%d", &number);
originalNumber = number;
while (originalNumber != 0)
{
remainder = originalNumber%10;
result += remainder*remainder*remainder;
originalNumber /= 10;
}
if(result == number)
printf("%d is an Armstrong number.",number);
else
printf("%d is not an Armstrong number.",number);
return 0;
}
Output:
Enter an integer: 1634
1634 is an Armstrong number.
1634 is an Armstrong number.
Another Example
Program for to check Armstrong number or not
#include <stdio.h>
#include <math.h>
int main()
{
int number, originalNumber, remainder, result = 0, n = 0 ;
printf("Enter an integer: ");
scanf("%d", &number);
originalNumber = number;
while (originalNumber != 0)
{
originalNumber /= 10;
++n;
}
originalNumber = number;
while (originalNumber != 0)
{
remainder = originalNumber%10;
result += pow(remainder, n);
originalNumber /= 10;
}
if(result == number)
printf("%d is an Armstrong number.", number);
else
printf("%d is not an Armstrong number.", number);
return 0;
}
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